A vessel with some head-space |
For the "nut to crack" the concentration 1 / e (0.368) was found as the first result and e was found indirectly as the reciprocal value (dilution factor). With a head-space in vessel A it is possible to use another way of gradual approximation. The start concentration is unknown, but nevertheless it is possible to calculate a dilution factor. Instead of the sequence: |
transfer - fill up - mix use add - mix - transfer |
In a variant with 4 steps, after addition of 1/4 of water to 4/4 of solution the dilution factor is 5/4 (1.25). After a repetition the dilution factor is 1.25 * 1.25. A total of 4 steps are possible until the equal-sized vessel B is full. | |||
Total dilution factor with vessel B full to the brim: | |||
With 4 steps: | 1.254 = (1 + 1/4)4 | = 2.44 | |
With 10 steps: | 1.110 = (1 + 1/10)10 | = 2.59 | |
With 100 steps: | (1 + 1/100)100 | = 2.70 | |
With 1000 steps: | (1 + 1/1000)1000 | = 2.72 | |
Up to infinite steps: | (1 + 1/n)n | = 2.718.. | |
The result is e and this formula is given in encyclopaedias, rather than the formula 1/e = (1 - 1/n)n, which was found in the "nut to crack". |