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A dilution factor named "e"
Some people may estimate that the final concentration in A will be 0.5 g/L, corresponding to a lowering of the original concentration of 1 g/L by a factor of 2.

But the dilution factor is  2.71828 .

Those who had never used  e  in practice did it just now. The name "e" was given by Leonard Euler in 1748.  e  appears in cases where a lot of very small steps are used, in particular an indefinite sum of indefinite small steps. The term "continuous" is used for such a process and continuous dilution is a very graphic example.

The final concentration after filling an equal-sized vessel B is  1/e = 0.368.   The next figure shows a model with two vessels B and C to be filled:


After filling of vessel B the concentration was 1 / e  =  0.368, during the filling of vessel C the concentration is again lessened by a factor e and thus the final result is:  1 / e / e  =  0.135.

Within the step-wise calculation of  0.368, the exponential form   0.753  was used instead of repeated multiplication  0.75 * 0.75 * 0.75.

For repeated division the same advantage will be drawn from  1 * e-3  instead of  1 /e /e /e.   Help with negative exponents

With a start concentration c0 = 1 the following formulas result for the concentration c:

Vessels Repeated
dilution
Total dilution
factor
c
formula
c
(c0 = 1)
11 /ee12.72 c0 * e-10.368
21 /e /ee27.39 c0 * e-20.135
31 /e /e /ee320.09 c0 * e-30.050
41 /e /e /e /ee4 54.60c0 * e-40.018
51 /e /e /e /e /ee5 148.41c0 * e-50.007
6.........